11/10/2023 0 Comments Dbforge studio for mysql developerSelect myTableid, as Priority from myTable where Description like '%' + - then with something at the beginning Select myTableid, as Priority from myTable where Description like + '%' - then with something at the end Select myTableid, as Priority from myTable where Description like - exact matches have highest priority Insert into id from ') - this function gives you a table with rows containing all the space separated words of the search like in this e.g., the output will be -ĭelete s from s join n on s.word = n.id - trimming out non-words hereĭeclare int = (select count(word) from - count of space separated words for search WordRank int Identity(1,1), - individual words are assinged priority order (in order of occurence/position)ĭeclare Table( - table to trim out auxiliary verbs, prepositions etc. Select 1 as Priority ,myTableid, code, Description from myTable order by Description If = 0) - if search string is empty, just return records ordered alphabetically infection in upper side with acute genitointestinal tract the searched string above should give rows containing the following VALUES this is the search script which can be optionally converted to a stored procedure /functionĭeclare varchar(max) = 'infection upper acute genito' - enter your search string here function to split space separated search string into individual wordsĬREATE FUNCTION. However, if you can't get that working on your DB for some reason, here is a performance-intensive solution: - table to search inĭescription varchar(200) NOT NULL - this column contains the values we are going to search in This should ideally be done with the help of SQL Server full text search if using that. If you have a different word delimiter, you may need to modify the function accordingly.įor reference, the query was run in dbForge Studio for SQL Server Please note that this function assumes that the words in the parameter are separated by spaces. This query will return all rows where Column1 contains all the specified words in any order. WHERE dbo.ContainsAllWords(Column1, 'word1 word2 word3') = 1 RETURN function takes two parameters: which is the column value you want to search within, and which is a space-separated string of words you want to find in the can then use this function in your query as follows: SELECT * Check if each word exists in the input string Here's an example of a SQL Server function that allows you to search for a variable number of words in a column: CREATE FUNCTION NVARCHAR(MAX) LEFT JOIN F2 ON T.Column1 NOT LIKE '%' + F2.Data + '%' INNER JOIN F1 ON T.Column1 LIKE '%' + F1.Data + '%' Get different and unique words for the searchįROM fnSplit(' ', 'word1 word2 word3') S - Contains words Search words word1, word2, word3 into MyTable.Column1: - Create a temporal table (the Data size depends on the length of the word) With MySQL: Auxiliar Function - Split by Returns all partsĬREATE FUNCTION.
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